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From: aznboysam Subject: Differential Eq.
| A function y(t) satisfies the differential equation dy/dx = y^2 cost and the inital condition y(0) = 1. a) find an explicit expression for y(1). b) for what value(s) of t between -pie and pie does y(t) have vertical asymptotes? c) find an expression for d^2y/dx^2 in terms of t only. so...I wrote in dy/dx = y^2cos x y(0) = 1 integral dy/y^2 = integral cos x dx and -1/y = sin x + c what do we do now? i| |
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