We have:
(1) x2yz = 12 (2) xy2z = 6 (3) xyz2 = 18
Adding equations we get: xyz(x+y+z) = 36 multiplying equations we get: (xyz)4 = 1296 xyz = 6 So 6(x+y+z)=36 x+y+z=6
View different answers : Soroban | Soarer
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