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Solution 2  by radagast

We have:

(1) x2yz = 12      (2) xy2z = 6       (3) xyz2 = 18

Adding equations we get:
xyz(x+y+z) = 36
multiplying equations we get:
(xyz)4 = 1296
xyz = 6
So
6(x+y+z)=36
x+y+z=6

View different answers : Soroban | Soarer

 

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