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Solution 11  by Soarer

n^2=1+...+(2n-1)
The sum S
=x[(1+x+x^2+...)+3x(1+x+...)+5x^2(1+....)+...)
=x[1/(1-x)+3x/(1-x)+5x^2/(1-x)+...]
=x/(1-x) [1+3x+5x^2+...]
=x/(1-x) [(1+x)+2x(1+x)+3x^2(1+x)+...]
=x(1+x)/(1-x) [1+2x+3x^2+...]
=x(1+x)/(1-x) [1+x+x^2+...+x+x^2+....+..]
=x(1+x)/(1-x) [(1/1-x)+x/(1-x)+x^2/(1-x)+...]
=x(1+x)/(1-x)^2 [1+x+x^2+...]
=x(1+x)/(1-x)^3

View other answers by:bugzpodder|ali |Ant|kstahmer

 

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